Opened 6 years ago

Last modified 4 years ago

#8673 new feature request

GHC could generate GADT record selectors in more cases

Reported by: simonpj Owned by:
Priority: normal Milestone:
Component: Compiler (Type checker) Version: 7.6.3
Keywords: GADTs Cc: p.k.f.holzenspies@…
Operating System: Unknown/Multiple Architecture: Unknown/Multiple
Type of failure: None/Unknown Test Case:
Blocked By: Blocking:
Related Tickets: Differential Rev(s):
Wiki Page:

Description (last modified by simonpj)

Philip Holzenspies writes (in email to ghc-users): I was playing around with GADT-records again and ran into behaviour that I'm not sure is intentional. Given this program:


data FooBar x a where
   Foo :: { fooBar :: a } -> FooBar Char a
   Bar :: { fooBar :: a } -> FooBar Bool a

GHC tells me this:

     Constructors Foo and Bar have a common field `fooBar',
       but have different result types
     In the data declaration for `FooBar'
Failed, modules loaded: none.

The user guide does say (section 7.4.7): "However, for GADTs there is the following additional constraint: every constructor that has a field f must have the same result type (modulo alpha conversion)." So this behaviour is documented in the user guide. However, it seems reasonable that in the case above, where all the relevant variables are exposed in the result type of both constructors, this should be perfectly typeable.

In other words, shouldn't GHC be able to derive a type that is simply:

fooBar :: FooBar x a -> a


Is this something that was simply never implemented, but could be, or is this not decidable or prohibitively computationally complex?

Change History (4)

comment:1 Changed 6 years ago by simonpj

Description: modified (diff)


data Bar a where
  B1 :: { x :: b } -> Bar [b]
  B2 :: { x :: b } -> Bar [b]
  B3 :: Bar a

Now we can define a perfectly good selector

  x :: Bar [b] -> b
  x (B1 v) = v
  x (B2 v) = v

But this wouldn't work if the result types were different

data BadBar a where
  B1 :: { x :: b } -> Bar [b]
  B2 :: { x :: b } -> Bar b
  B3 :: Bar a

Now it's true that in your example the field mentions only *polymorphic* components, so there is a perfectly well-defined selector with the type you give. Indeed, it could be a bit more complicated:

data FooBar x a where
  Foo :: { fooBar :: a } -> FooBar Char [a]
  Bar :: { fooBar :: a } -> FooBar Bool [a]

Then there is a reasonable selector with type

  fooBar :: FooBar b [a] -> a

So what is the general rule? When exactly is there a well-defined selector type, and what is that type? Notice that in the type of fooBar we had to generalise over the Char/Bool difference, but maintain the [a] part. Indeed it might all be part of one type:

data FooBar2 x where
  Foo2 :: { fooBar2 :: a } -> FooBar2 (Char, [a])
  Bar2 :: { fooBar2 :: a } -> FooBar2 (Bool, [a])

So now

  fooBar2 :: FooBar2 (x, [a]) -> a

where we generalise part of the type.

So, on reflection, there must be a more permissive rule than the one GHC currently implements. If someone wants to figure out the general rule, express it formally, say what the user manual would say, we could discuss whether the cost benefit ratio is good enough to be worth implementing.

comment:2 Changed 6 years ago by br1

I just also hit this limitation, but I'm not sure if my case was included in the cases already discussed. I want to do something like:

data Bar a where
  B1 :: { x :: Int } -> Bar Int
  B2 :: { x :: Char } -> Bar Char 

comment:3 Changed 4 years ago by thomie

Component: CompilerCompiler (Type checker)

comment:4 Changed 4 years ago by thomie

Keywords: GADTs added
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